TOPIC-02 · Engineering guide
Balanced Three-Phase Power and Current
For a balanced three-phase load, apparent power is √3 × line voltage × line current. At 400 V, 10 A and 0.8 lagging, active power is 5542.56258422 W, apparent power is 6928.203230276 VA, and lagging reactive power is 4156.921938165 var.
Formula, variables and conditions
k = sqrt(3) for balanced three-phase, otherwise 1 S = k × V × I P = S × pf Q = +S × sqrt(1 − pf²) when lagging, and the opposite sign when leading From active power, I = P / (k × V × pf).
Variables and units
- V: phase voltage for single-phase, line-to-line voltage for balanced three-phase. Unit V.
- I: line current in A.
- pf: displacement power factor, greater than 0 and at most 1.
- P, S, Q: active watts, apparent volt-amperes, and reactive vars.
Conditions
- Sinusoidal steady state. The three-phase path assumes balance.
- Motor-measurement mode is a different question: it divides measured input watts by the apparent power from RMS voltage and current. This example is from-current, not motor-measurement.
- The calculation record stores SRC-002 with url: null. The project source register names the OpenStax sections below as previously checked. This guide does not write a URL onto the calculation record.
Worked example
Locked TC-004 fixture: balanced-three, from-current, lagging.
- Line voltage
- 400 V
- Line current
- 10 A
- Power factor
- 0.8 lagging
- Active power P
- 5542.56258422 W
- Apparent power S
- 6928.203230276 VA
- Reactive power Q
- 4156.921938165 var
S = sqrt(3) × 400 × 10. P = S × 0.8. Q = S × 0.6 because sin(acos(0.8)) = 0.6 for a lagging load. Line current stays 10 A in from-current mode.
Boundaries and common mistakes
Boundaries
- Harmonics, unbalance and code compliance are not evaluated.
- A leading load uses a negative Q. The 400 V example above is lagging.
- Three-phase fault current is a different calculator and stays in Wiring, circuits & protection.
Common mistakes
- Dropping √3 and treating 400 V × 10 A as the three-phase apparent power.
- Using a phase voltage and √3 together.
- Reading power factor as P/S and then applying it to shaft power. This mode does not know efficiency.