TOPIC-03 · Engineering guide
Steady-State Cable Thermal Current Estimate
The estimate is the current whose I²R heat matches the entered temperature rise across one thermal resistance. For the base fixture, resistance at the maximum temperature is 0.0128 Ω/m and the current is sqrt(60 / (0.0128 × 0.5)).
Formula, variables and conditions
R(Tmax) = R_Ω/km × (1 + α × (Tmax − Tref)) / 1000 I = sqrt( (Tmax − Tambient) / (R(Tmax) × thermalResistance) ) Derating against a reference ambient is I(Tambient) / I(Treference).
Variables and units
- R_Ω/km: AC resistance at the reference conductor temperature, in ohms per kilometre.
- α: temperature coefficient per kelvin.
- Tmax, Tref, Tambient, Treference: temperatures in °C. Ambient values must be below Tmax.
- thermalResistance: kelvin-metres per watt, one lumped path, greater than 0.
Conditions
- One conductor, continuous constant current, steady ambient, conductor heat only.
- The resistance factor must stay positive.
- Sources SRC-025, SRC-026 and SRC-027 are stored as review-required. Their pages are scope or context links. No IEC table is reproduced and the status is not promoted to verified.
Worked example
Base fixture from the BACKLOG-013 unit test.
- Resistance
- 10 Ω/km at 20 °C
- α / thermal resistance
- 0.004 /K and 0.5 K·m/W
- Temperatures
- Tmax 90 °C, ambient 30 °C, reference ambient 20 °C
- R at 90 °C
- 0.0128 Ω/m
- Current at 30 °C
- sqrt(60 / (0.0128 × 0.5)) A
- Reference current and ratio
- sqrt(70 / (0.0128 × 0.5)) A, derating sqrt(60 / 70)
Hotter ambient lowers the current. The unit test also locks a second illustrative point at 542.304878105656 A when resistance is 0.2 Ω/km, α is 0.00393 /K and thermal resistance is 0.8 K·m/W, with the same 90/30/20 °C temperatures. Neither number is a catalogue rating.
Boundaries and common mistakes
Boundaries
- Standards compliance, cable construction, installation method and protection are marked not-evaluated.
- The warning on the calculation record says this is not a safe, approved or guaranteed conductor rating.
- Voltage drop is a separate model. A thermal-current result does not imply a voltage-drop pass.
Common mistakes
- Forgetting to convert Ω/km to Ω/m. The divisor is 1000.
- Using the reference-temperature resistance inside the square root without the α correction.
- Publishing the result as an IEC 60287 ampacity. The stored IEC links were not used as copied tables.