CASE-006 · Teaching Example
Transformer Turns Ratio
What secondary winding voltage and turns ratio does the ideal model return for 100 to 10 turns at 230 V?
Teaching example—not a real installation.
01
Teaching inputs
Fixed values from the versioned calculation fixture.
- Phase and connection
- Single-phase, single / single
- Voltage mode
- Winding-phase on both sides
- Turns
- N1 = 100, N2 = 10
- Primary voltage
- 230 V
- Solve mode
- solve-voltage-ratio, then the reverse solve-turns-ratio check
02
Calculation path
Each transformation stays visible.
- 1
Apply the ideal ratio
Winding-phase voltages stay in proportion to the turns. Nothing in this step is a loaded voltage.
V2 = V1 × N2 / N1 = 230 × 10 / 100 - 2
Read the turns ratio
The ratio reported with the voltage solution is N1/N2.
N1 / N2 = 100 / 10 = 10 - 3
Reverse the known voltages
The unit test also solves the turns ratio from 230 V and 23 V and gets 10. That is the same fixture run backwards, not a second installation.
V1 / V2 = 230 / 23 = 10
03 · Result
The modeled outcome.
Teaching example—not a real installation. Results apply only to the stated fixture inputs.
| Measure | Calculated value | Interpretation |
|---|---|---|
| Secondary voltage | 23 V | Ideal magnitude |
| Turns ratio | 10 | 100 / 10 |
| Reverse ratio | 10 | From 230 V and 23 V |
Teaching Example: the ideal model returns 23 V and a turns ratio of 10. It does not estimate regulation.
04
Boundaries & sources
What the result does—and does not—support.
- No impedance drop, regulation, vector-group shift, taps or unbalance.
- A wye line-to-line voltage would be divided by sqrt(3) first. This fixture does not do that.
- The result does not select a transformer.
Method references
PowerEngineerLab internal method · TOOL-021 model 1.1.0 · dataset user-input-v1
SRC-058 OpenStax, induced EMF and magnetic flux (checked 2026-10-14)Continue exploring